I'll bet if you put a diode across a long enough dipole antenna you could get the thief to run on the ambient RF alone.
I'm working on a mosfet joule thief that is powered by radio frequency alone, no battery I'll post some pics once I have it built.
Quote from: QwazyWabbit on March 31, 2011, 02:52:01 PMI'll bet if you put a diode across a long enough dipole antenna you could get the thief to run on the ambient RF alone.Dude did you read my post.....here:QuoteI'm working on a mosfet joule thief that is powered by radio frequency alone, no battery I'll post some pics once I have it built.
Quote from: astral on March 31, 2011, 03:01:01 PMQuote from: QwazyWabbit on March 31, 2011, 02:52:01 PMI'll bet if you put a diode across a long enough dipole antenna you could get the thief to run on the ambient RF alone.Dude did you read my post.....here:QuoteI'm working on a mosfet joule thief that is powered by radio frequency alone, no battery I'll post some pics once I have it built. Yes, I did read your post completely and I agreed.No, you don't need a full-wave bridge, but it might help. The problem with a bridge will be the lost voltage due to the forward drop of the conducting diodes. You will lose a lot of energy overcoming that. You can get several microamps off a dipole like this:Diode: 1n4148 Capacitor: .1 uF disc ceramic.------------------------------------------------------------->|------------------------------------------------------------------ | | ----) |-------- | | 0 0 (-) (+) Why no full-wave? Because it's not one frequency, you are getting the full spectrum of RF around, including 60Hz (in US) or 50Hz. The circuit is not very frequency selective except for the resonant frequency of the antenna as a 1/2 wave of some radio frequency. (150MHz for a 2M dipole for instance). This is the basis for simple field strength meters if you put a 50 uA ammeter movement across the terminals. The longer it is the better. The Joule thief won't care about the filtration of the energy it needs since it's already a chopper to start with.PS: I am a EE, ECET and an active ham radio operator, advanced class since 1974.
From the winding video it looks like it's 10 turns of each winding around the toroid. (I think the first link said 20 turns but it seems to be 10 turns with the two goofy dudes.The failure mode of the transistor might tell you what you're doing wrong. A 2N3904 has a Vce max of 40 or 50 volts so you should not be failing there.
Don't use a big inductor, a small toroid like they use will be sufficient for powering an LED. I think the white LED's pull about 20 mA forward current at 3V
The 2N3904 can handle Ic max of 200 mA easily in a TO-92 case. If you are blowing the transistor then it's possibly due to too much current through the base-emitter junction. If the transistor is opening between C-E then it's over-voltage collector-emitter. If it's opening B-E then it's over current in the base. Cracking the case and letting the magic smoke out is excess power dissipation.
If you look at the circuit the LED's forward voltage drop clamps the C-E voltage across the transistor, what's happening is the collapsing magnetic field of the inductor is producing the diode forward current when the transistor is OFF. If you hook the diode up backwards or you don't have a diode the inductor can over-volt the transistor. When the transistor is ON it's pulling max current out of the battery through the inductor to build up a nice fat magnetic field, the changing current is what tickles the base-emitter junction into turning the transistor on and off via Vbatt. * di/dt through the secondary. You end up with a very high frequency oscillation as the magnetic fields build and collapse.DON'T use a new battery. It needs to be very depleted before this circuit won't over-produce. The battery is being shorted by the transistor through the inductor so you can pop a transistor pretty easily when that inductor kicks back.
I am not sure an open air coil will have enough inductance to kick the oscillator, trial and error there I think. 2 or 3 turns in a 10' x 10' room maybe? Ring the primary and secondary VERY close together around the ceiling.You definitely won't get enough voltage out of it from RF to charge a phone battery.
can i use this to power my house?